Monday, 28 September 2020

SOLVED - jQuery Ajax POST example with PHP

jQuery Ajax POST example with PHP

PROBLEM -
<form name="foo" action="form.php" method="POST" id="foo"> <label for="bar">A bar</label> <input id="bar" name="bar" type="text" value="" /> <input type="submit" value="Send" /> </form>
 

HTML:

<form id="foo">
    <label for="bar">A bar</label>
    <input id="bar" name="bar" type="text" value="" />

    <input type="submit" value="Send" />
</form> 
 

jQuery:

// Variable to hold request var request; // Bind to the submit event of our form $("#foo").submit(function(event){ // Prevent default posting of form - put here to work in case of errors event.preventDefault(); // Abort any pending request if (request) { request.abort(); } // setup some local variables var $form = $(this); // Let's select and cache all the fields var $inputs = $form.find("input, select, button, textarea"); // Serialize the data in the form var serializedData = $form.serialize(); // Let's disable the inputs for the duration of the Ajax request. // Note: we disable elements AFTER the form data has been serialized. // Disabled form elements will not be serialized. $inputs.prop("disabled", true); // Fire off the request to /form.php request = $.ajax({ url: "/form.php", type: "post", data: serializedData }); 
 // Callback handler that will be called on success
    request.done(function (response, textStatus, jqXHR){
        // Log a message to the console
        console.log("Hooray, it worked!");
    });

    // Callback handler that will be called on failure
    request.fail(function (jqXHR, textStatus, errorThrown){
        // Log the error to the console
        console.error(
            "The following error occurred: "+
            textStatus, errorThrown
        );
    });

    // Callback handler that will be called regardless
    // if the request failed or succeeded
    request.always(function () {
        // Reenable the inputs
        $inputs.prop("disabled", false);
    });

});
 

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