Saturday 29 October 2011

TRIANGLE ROTATION PROGRAM

TRIANGLE ROTATION PROGRAM IN C++

#include<stdio.h>
#include<conio.h>
#include<graphics.h>
#include<process.h>
#include<math.h>
void triangle(int x1,int y1,int x2,int y2,int x3,int y3);
void Rotate(int x1,int y1,int x2,int y2,int x3,int y3);
void main()
{
    int gd=DETECT,gm;
    int x1,y1,x2,y2,x3,y3;
    initgraph(&gd,&gm,"c:\\tc\\bgi");
    printf("Enter the 1st point for the triangle:");
    scanf("%d%d",&x1,&y1);
    printf("Enter the 2nd point for the triangle:");
    scanf("%d%d",&x2,&y2);
    printf("Enter the 3rd point for the triangle:");
    scanf("%d%d",&x3,&y3);
    triangle(x1,y1,x2,y2,x3,y3);
    getch();
    cleardevice();
    Rotate(x1,y1,x2,y2,x3,y3);
    setcolor(1);
    triangle(x1,y1,x2,y2,x3,y3);
    getch();
}
void triangle(int x1,int y1,int x2,int y2,int x3,int y3)
{
   line(x1,y1,x2,y2);
   line(x2,y2,x3,y3);
   line(x3,y3,x1,y1);
}
void Rotate(int x1,int y1,int x2,int y2,int x3,int y3)
{
    int x,y,a1,b1,a2,b2,a3,b3,p=x2,q=y2;
    float Angle;
    printf("Enter the angle for rotation:");
    scanf("%f",&Angle);
    cleardevice();
    Angle=(Angle*3.14)/180;
    a1=p+(x1-p)*cos(Angle)-(y1-q)*sin(Angle);
    b1=q+(x1-p)*sin(Angle)+(y1-q)*cos(Angle);
    a2=p+(x2-p)*cos(Angle)-(y2-q)*sin(Angle);
    b2=q+(x2-p)*sin(Angle)+(y2-q)*cos(Angle);
    a3=p+(x3-p)*cos(Angle)-(y3-q)*sin(Angle);
    b3=q+(x3-p)*sin(Angle)+(y3-q)*cos(Angle);
    printf("Rotate");
    triangle(a1,b1,a2,b2,a3,b3);
}

2 comments:

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    Replies
    1. It is the destination coordinate point for x-axis.
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